Differences Between `Foldl` and `Foldr`

(blog.haskell.org)

71 points | by signa11 4 days ago

4 comments

  • s-zeng 2 hours ago
    A neat fact about foldr on lists, unlike foldl, is that it actually passes control flow entirely to the accumulating function on each fold step. That means you can use foldr to implement arbitrary traversals of lists, including foldl' or list traversals that exit early. See https://github.com/quchen/articles/blob/master/useful_techni...
    • someonebaggy 47 minutes ago
      At some point doesn't it become easier to write the function explicitly? As in

          go [] = ...
          go head:remainder = ...
      
      instead of hacking it together with a fold?
      • bos 5 minutes ago
        If you don’t already know about folds, arguably yes.

        If you do, then a quick glance at whether you’re using foldl’ or foldr tells you about what the function is allowed to do, which cuts down a little on comprehension.

        List traversals are typically compact enough that there’s not a huge difference either way.

        One advantage of using a fold, even in these cases, is that newcomers to Haskell often get so carried away with (and confused by) the power of pattern matching that they’ll write bizarre overly-complicated list traversals by hand, when a simpler mechanism exists that they just haven’t yet internalized.

  • layer8 1 hour ago
    > Both foldl and foldr traverse the structure in the same order, which in the case of lists means left to right.

    This characterization is debatable, unless one is assuming single-linked lists, which by definition can only be traversed from left to right (even moreso in a lazy language where the list may have indefinite length). When implemented in a strict language on an array or a double-linked list, the traversal order will be right-to-left for foldr.

    A more accurate statement would be that in Haskell, lists can only be traversed from left to right, and therefore the implementations of both foldl and foldr in Haskell are necessarily based on that.

    • kccqzy 1 hour ago
      Right. The article is only talking about the foldr and foldl functions on Haskell lists. In the addendum it talks about the functions on other data structures (presumably the implementation of instances of the Foldable class). It would be more instructive to examine the definitions of foldr and foldl on other types such as Map instead of yet another custom list type.

      I actually think examining the definitions of folds in Map (a binary tree) is perhaps pedagogically a better starting point. The singly linked list is inherently left biased. A binary tree is symmetrical. So the implementation of foldr and foldl on a binary tree is more similar: literally flipping the order of the arguments to the accumulation function and swapping the left and right children. Furthermore you can induce the “early termination” by laziness behavior by adjusting whether your accumulation function forces the first or second argument. And all four versions foldr, foldl, foldr' and foldl' are meaningful.

    • someonebaggy 49 minutes ago
      A list in Haskell is a singly-linked list with the possibility of tail sharing.
  • mbauman 1 hour ago
    To a CS person, "ordering" is about the arrangement of a list. But pretty much everyone else will think about a *temporal* order of operations. And in that case it is indeed "starting" from the right or left.

    It just gets confusing when you're dealing with lots of deferred/lazy operations.

  • kccqzy 1 hour ago
    I noticed that AI likes to overuse foldl' and foldr (especially foldr) including analogous versions on Maps, even when there are simpler and more straightforward ways to achieve the same thing.

    When AI writes foldr with a complicated accumulation function, I’d prompt AI to define a custom monoidal structure and then use foldMap. Then the reader doesn’t have to think about the asymmetric accumulation function and instead think about the mapping operation and the associative combine function separately. Factoring out the two jobs of the accumulation function is a great trick to improve readability: excellent tradeoff if the human is mostly reading the code.

    • Drupon 48 minutes ago
      Doesn't using AI render the main advantage of Haskell (telling everyone you can write software in Haskell) somewhat pointless?
      • nosman 13 minutes ago
        In my experience, AI does really well with a good type system. It tries something, if it doesn't compile, looks at the message, fixes, etc etc.

        The compiler itself acts as a steering function for the AI. I've also had this experience with Rust.

      • kccqzy 39 minutes ago
        The advantage of Haskell is higher quality code with fewer bugs even when you write fewer unit tests. The advantage is the same whether humans write the code or AI writes it.

        This might not be noticeable if you only write short programs: if the human can put the entire program in the head or if the AI can keep the whole thing in the context window. It matters much more when the program gets bigger.